Organic Chemistry is really freakin' cool!!!!....no...really!
So I have the last of my regular Organic Chemistry exams today. My mind is filled with such pleasantries as hydroboration, oxymercuration, dehydrohalogenation, alkyne and alkene formations and subsequent hydrogenations, Zaitzev and Hoffman rules, Markovnikov and anti-Markovnikov hydrogen addition, E2 elimination on chair conformations wherein only one diaxial hydrogen on a beta carbon is avaiable to be removed, but the ring is in an energetically unfavorable conformation and who could forget the simmons smith reagent as a tool for cyclopropanation.
So here are the more important things
for oxymercuration the second step of the mechanism uses NaBH4
for hydroboration the second step of the mechanism uses H2O2 and -OH
for dihydroxylation (OsO4) NaHSO3 is used with it.
HBr will be deprotonated and the created proton will add via markovnikov to an alkene or alkyne, and the bromide ion will add to the opposite side without control of stereochemistry. In the presence of peroxides however the H that is pulled off will add anti-markovinkov with the bromide adding to the other side.
Retro-synthetic analysis is your friend when you are given a puzzle.....
Hot concentrated KMnO4 in OH gives you cleavage of double bonds and if it is a terminal alkene you will get bubbles of CO2 gas, while cold KMnO4 will give you syn addition diol formation.
Ozonolysis of Alkynes will give us CO2 gas if it is a terminal alkyne, with alkenes we get some cleavages. We uses Ozone in the presence of CH2Cl2.
Yeah you guys are bored so I'll leave ya'll with the quote of the day.
Wish me luck....
QUOTE OF THE DAY
All of my neurons are functioning smoothly
yet still I'm a cyborg just like you
- Bad Religion
So here are the more important things
for oxymercuration the second step of the mechanism uses NaBH4
for hydroboration the second step of the mechanism uses H2O2 and -OH
for dihydroxylation (OsO4) NaHSO3 is used with it.
HBr will be deprotonated and the created proton will add via markovnikov to an alkene or alkyne, and the bromide ion will add to the opposite side without control of stereochemistry. In the presence of peroxides however the H that is pulled off will add anti-markovinkov with the bromide adding to the other side.
Retro-synthetic analysis is your friend when you are given a puzzle.....
Hot concentrated KMnO4 in OH gives you cleavage of double bonds and if it is a terminal alkene you will get bubbles of CO2 gas, while cold KMnO4 will give you syn addition diol formation.
Ozonolysis of Alkynes will give us CO2 gas if it is a terminal alkyne, with alkenes we get some cleavages. We uses Ozone in the presence of CH2Cl2.
Yeah you guys are bored so I'll leave ya'll with the quote of the day.
Wish me luck....
QUOTE OF THE DAY
All of my neurons are functioning smoothly
yet still I'm a cyborg just like you
- Bad Religion
1 Comments:
i think your spanish posts were easier to understand... and i haven't taken spanish since fifth grade...
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